Difference between revisions of "Mathematical formula"

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<math>\scriptstyle\left(3n+1\right)^2=\left[\left[10\sdot\left[\frac{1}{3}\sdot\left(3n\right)\right]^2\right]-\left[\frac{1}{3}\sdot\left(3n\right)\right]^2\right]+3n+\left(3n+1\right)</math>]]
 
<math>\scriptstyle\left(3n+1\right)^2=\left[\left[10\sdot\left[\frac{1}{3}\sdot\left(3n\right)\right]^2\right]-\left[\frac{1}{3}\sdot\left(3n\right)\right]^2\right]+3n+\left(3n+1\right)</math>]]
  
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<div class="mw-collapsible mw-collapsed"><math>\scriptstyle bx=\sqrt[3]{c}</math><div class="mw-collapsible-content">
 
{{#annotask:
 
{{#annotask:
 
[[category: #linear equation]]
 
[[category: #linear equation]]
 
[[comment: bx=³√c]]
 
[[comment: bx=³√c]]
}}
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}}</div></div>
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<br>
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<div class="mw-collapsible mw-collapsed"><math>\scriptstyle c=\sqrt[3]{bx}</math><div class="mw-collapsible-content">
 
{{#annotask:
 
{{#annotask:
 
[[category: #linear equation]]
 
[[category: #linear equation]]
 
[[comment: c=³√bx]]
 
[[comment: c=³√bx]]
}}
+
}}</div></div>
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<br>
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<div class="mw-collapsible mw-collapsed"><math>\scriptstyle ax^2=\sqrt[3]{c}</math><div class="mw-collapsible-content">
 
{{#annotask:
 
{{#annotask:
 
[[category: #quadratic equation]]
 
[[category: #quadratic equation]]
 
[[comment: ax²=³√c]]
 
[[comment: ax²=³√c]]
}}
+
}}</div></div>
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<br>
 +
<div class="mw-collapsible mw-collapsed"><math>\scriptstyle c=\sqrt[3]{ax^2}</math><div class="mw-collapsible-content">
 
{{#annotask:
 
{{#annotask:
 
[[category: #quadratic equation]]
 
[[category: #quadratic equation]]
 
[[comment: c=³√ax²]]
 
[[comment: c=³√ax²]]
}}
+
}}</div></div>
 +
<br>
 +
<div class="mw-collapsible mw-collapsed"><math>\scriptstyle ax^3=\sqrt[3]{c}</math><div class="mw-collapsible-content">
 
{{#annotask:
 
{{#annotask:
 
[[category: #cubic equation]]
 
[[category: #cubic equation]]
 
[[comment: ax³=³√c]]
 
[[comment: ax³=³√c]]
}}
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}}</div></div>
 
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<br>
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<div class="mw-collapsible mw-collapsed"><math>\scriptstyle4\sdot\left(x^2+8\right)=x^4</math><div class="mw-collapsible-content">
 
{{#annotask:
 
{{#annotask:
 
[[category: #biquadratic equation]]
 
[[category: #biquadratic equation]]
 
[[comment: 4(x²+8)=x⁴]]
 
[[comment: 4(x²+8)=x⁴]]
}}
+
}}</div></div>

Revision as of 08:33, 7 April 2019


\scriptstyle\left(3n+1\right)^2=\left[\left[10\sdot\left[\frac{1}{3}\sdot\left(3n\right)\right]^2\right]-\left[\frac{1}{3}\sdot\left(3n\right)\right]^2\right]+3n+\left(3n+1\right)

[Expand]\scriptstyle bx=\sqrt[3]{c}


[Expand]\scriptstyle c=\sqrt[3]{bx}


[Expand]\scriptstyle ax^2=\sqrt[3]{c}


[Expand]\scriptstyle c=\sqrt[3]{ax^2}


[Expand]\scriptstyle ax^3=\sqrt[3]{c}


[Expand]\scriptstyle4\sdot\left(x^2+8\right)=x^4