Difference between revisions of "Mathematical formula"
From mispar
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− | [[(3n+1)²=((10·(⅓·3n)²)-(⅓·3n)²)+3n+(3n+1)]] | + | |
+ | [[(3n+1)²=((10·(⅓·3n)²)-(⅓·3n)²)+3n+(3n+1)| | ||
+ | <math>\scriptstyle\left(3n+1\right)^2=\left[\left[10\sdot\left[\frac{1}{3}\sdot\left(3n\right)\right]^2\right]-\left[\frac{1}{3}\sdot\left(3n\right)\right]^2\right]+3n+\left(3n+1\right)</math>]] | ||
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[[category: mathematical formula]] | [[category: mathematical formula]] | ||
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