Difference between revisions of "Mathematical formula"
From mispar
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<math>\scriptstyle\left(3n+1\right)^2=\left[\left[10\sdot\left[\frac{1}{3}\sdot\left(3n\right)\right]^2\right]-\left[\frac{1}{3}\sdot\left(3n\right)\right]^2\right]+3n+\left(3n+1\right)</math> | <math>\scriptstyle\left(3n+1\right)^2=\left[\left[10\sdot\left[\frac{1}{3}\sdot\left(3n\right)\right]^2\right]-\left[\frac{1}{3}\sdot\left(3n\right)\right]^2\right]+3n+\left(3n+1\right)</math> | ||
| − | [[(3n+1)²=(( | + | [[(3n+1)²=((10·(⅓·3n)²)-(⅓·3n)²)+3n+(3n+1)]] |
{{#annotask: | {{#annotask: | ||
[[category: mathematical formula]] | [[category: mathematical formula]] | ||
}} | }} | ||
Revision as of 05:52, 20 October 2018
![\scriptstyle\left(3n+1\right)^2=\left[\left[10\sdot\left[\frac{1}{3}\sdot\left(3n\right)\right]^2\right]-\left[\frac{1}{3}\sdot\left(3n\right)\right]^2\right]+3n+\left(3n+1\right)](/mediawiki/images/math/2/a/f/2af90eb131ece9e62879b03d8922a419.png)
(3n+1)²=((10·(⅓·3n)²)-(⅓·3n)²)+3n+(3n+1)
no such category found: mathematical formula
