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Divide a Number Problems

From Mispar
Revision as of 06:08, 23 May 2019 by Aradin (talk | contribs)

Divide Ten into Two Parts

{a+b=10a2=4⋅(a⋅b)
no such category found: #divide 10 into two parts


{a+b=10a2=(1+12)⋅(a⋅b)
no such category found: #divide 10 into two parts


{a+b=10102=16⋅a2
no such category found: #divide 10 into two parts


{a+b=10102=(6+14)⋅a2
no such category found: #divide 10 into two parts


{a+b=10ba=5
no such category found: #divide 10 into two parts


{a+b=10ba=4
no such category found: #divide 10 into two parts


{a+b=10a2=9b
no such category found: #divide 10 into two parts


{a+b=10a⋅b=21
no such category found: #divide 10 into two parts


{a+b=10ab+ba=2+16
no such category found: #divide 10 into two parts


{a+b=10ab−ba=3+34
no such category found: #divide 10 into two parts


{a+b=10b2−a2=50
no such category found: #divide 10 into two parts


{a+b=10a2=14b
no such category found: #divide 10 into two parts


{a+b=10(a−b)2=20+14
no such category found: #divide 10 into two parts


{a+b=10(b−a)2−a2=32
no such category found: #divide 10 into two parts


{a+b=103a=b⋅8
no such category found: #divide 10 into two parts


{a+b=10(a−b)2⋅a=(20+14)a
no such category found: #divide 10 into two parts


{a+b=10(a⋅b)⋅a=21a
no such category found: #divide 10 into two parts


{a+b=10(a−b)2⋅(7+19)=(a⋅b)2
no such category found: #divide 10 into two parts


{a+b=10[(a⋅b)+a2]⋅a=[a⋅(12⋅a)]2+36
no such category found: #divide 10 into two parts


Divide Ten into Three Parts

{a+b+c=10a2+b2=c2a⋅c=b2
no such category found: #divide 10 into three parts