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Mathematical formula

From Mispar
Revision as of 18:12, 19 October 2018 by Aradin (talk | contribs) (Created page with "{{#annot:|513|PXMZ}}<math>\scriptstyle\left(3n+1\right)^2=\left[\left[10\sdot\left[\frac{1}{3}\sdot\left(3n\right)\right]^2\right]-\left[\frac{1}{3}\sdot\left(3n\right)\right]...")
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(3n+1)2=[[10⋅[13⋅(3n)]2]−[13⋅(3n)]2]+3n+[(3n+1)]