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Revision as of 10:31, 31 October 2017

$a x^{2} + b x + c = 0$

$(\binom{| s | + 2 (n - 1)}{n})$

Revision as of 10:30, 31 October 2017 edit Vermeul (talk \| contribs) Bureaucrats, Administrators 494 edits No edit summary ← Older edit		Revision as of 10:31, 31 October 2017 edit undo Vermeul (talk \| contribs) Bureaucrats, Administrators 494 edits No edit summary Newer edit →
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	<math style=\textstyle> ax^2 + bx + c = 0</math>		<math style=\textstyle> ax^2 + bx + c = 0</math>



	<math>\textstyle{\|s\|+2(n-1)\choose n}</math>		<math>\textstyle{\|s\|+2(n-1)\choose n}</math>