Mathematical formula: Difference between revisions

Revision as of 05:52, 20 October 2018

${(3 n + 1)}^{2} = [[10 \cdot {[\frac{1}{3} \cdot (3 n)]}^{2}] - {[\frac{1}{3} \cdot (3 n)]}^{2}] + 3 n + (3 n + 1)$

@@ Line 1: / Line 1: @@
 <math>\scriptstyle\left(3n+1\right)^2=\left[\left[10\sdot\left[\frac{1}{3}\sdot\left(3n\right)\right]^2\right]-\left[\frac{1}{3}\sdot\left(3n\right)\right]^2\right]+3n+\left(3n+1\right)</math>
-[[(3n+1)²=((10·⅓·(3n)²)-(3n)²)+3n+(3n+1)]]
+[[(3n+1)²=((10·(⅓·3n)²)-(⅓·3n)²)+3n+(3n+1)]]
 {{#annotask:
 	[[category: mathematical formula]]
 }}