Main Page: Difference between revisions

Revision as of 16:52, 6 August 2017

$a x^{2} + b x + c = 0$

$(\binom{| s | + 2 (n - 1)}{n})$

Revision as of 16:52, 6 August 2017 edit Aradin (talk \| contribs) Bureaucrats, smwadministrator, smwcurator, Administrators 46,417 edits No edit summary ← Older edit		Revision as of 16:52, 6 August 2017 edit undo Aradin (talk \| contribs) Bureaucrats, smwadministrator, smwcurator, Administrators 46,417 edits No edit summary Newer edit →
Line 1:		Line 1:


	<math\textstyle> ax^2 + bx + c = 0</math>		<math>\textstyle{ax^2 + bx + c = 0}</math>


	<math>\textstyle{\|s\|+2(n-1)\choose n}</math>		<math>\textstyle{\|s\|+2(n-1)\choose n}</math>